#4 problem 6

We did the setup for problem 6 in class today.

The way you need to set it up is by giving each particle an equation with two components: X and Y. So, whatever height your first particle was at will be its y equation, I.E. Y=25. The x equation will be X = vt, I.E. x=2.5t. This is the particle moving at constant velocity. For the second particle, the one starting at the origin, your equations will need to have cos(∂) or sin(∂). These will use the acceleration equation for distance. So 1/2at^2 cos/sin (∂). In my case, I ended up with x=.195t^2sin(∂) and y=.195t^2cos(∂). I won't go any farther than this, other than to say that you need to have all the t's be the same, x=x, and y=y. If you need more help, ask me in class or ask Doc Lane.

Webassign #4

Heads up on webassign, problem 6 looks like it might be a doozy.

Webassign #4 notation

Your notation for problem two should look like this: x i ±y j ±z k

If it doesn't, it will come out horribly horribly wrong.

TODAY IN PHYSICS CLASS

We went over the test from last Friday. If you got less than a 75, you have to make it up. We also talked a small amount about what portions of calculus we really need. (All of it)

Webassign #4

Webassign #4 is up, so if you want to get a head start I'd suggest going for it.

Woohoo

I've made a blog.