#4 problem 6

We did the setup for problem 6 in class today.

The way you need to set it up is by giving each particle an equation with two components: X and Y. So, whatever height your first particle was at will be its y equation, I.E. Y=25. The x equation will be X = vt, I.E. x=2.5t. This is the particle moving at constant velocity. For the second particle, the one starting at the origin, your equations will need to have cos(∂) or sin(∂). These will use the acceleration equation for distance. So 1/2at^2 cos/sin (∂). In my case, I ended up with x=.195t^2sin(∂) and y=.195t^2cos(∂). I won't go any farther than this, other than to say that you need to have all the t's be the same, x=x, and y=y. If you need more help, ask me in class or ask Doc Lane.